**CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.6 Solutions : Explain why 7×11× 13 + 13 and 7×6×5×4×3×2×1+5 are composite numbers.**

Hy Friends Welcome On **NCERT MATHS SOLUTIONS** !! Today we are going to solve the Question :** ”Explain why 7×11× 13 + 13 and 7×6×5×4×3×2×1+5 are composite numbers.” **of** Exercise 1.2 Question No 6 Solutions (Real Numbers)** of Class 10th, which will prove to be very helpful for you.

# CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.6 Solutions

If you are a student of CBSE, today we are going to give you the **CBSE / NCERT** **Chapter : Real Numbers ** **Exercise 1.2 Question No – 6** **Solutions** . Hope you like this post about Class 10th Maths Solution.

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**Real Numbers CHAPTER : 1**

Symbol of real numbers (ℝ) In mathematics, the real number is the value presented to any amount corresponding to the simple line. Actual numbers include all rational numbers such as -5 and fractional numbers such as 4/3 and all irrational numbers such as √2 (1.41421356 …, square root of 2, an unregulated algebraic number). By incorporating the ample numbers in the actual numbers, they can be presented from the eternal points that can be attributed on a line in the form of a real number line.

**Exercise- 1.2 Question No. 6 : ****Explain why 7×11× 13 + 13 and 7×6×5×4×3×2×1+5 are composite numbers.**

**Class 10 Exercise 1.2 Question No.6 Solutions**

Number are of two types – prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself.!

It can be observed that 7 × 11 × 13 +13 ( 7 × 11 + 1)

= 13 (77 + 1)

= 13 × 78

= 13 × 13 × 6

**The given expression has 6 and 13 as its factors. Therefore, it is a composite number.**

= 7×6×5×4×3×2×1+5

= 5 (7×6×5×4×3×2×1 +1)

= 5 × (1008 + 1 )

= 5 × 1009

1009 cannot be factorised further. Therefore, the given expression has 5 and 1009 as its fac tors. Hence, it is a composite number.

**CLICK ON RED BOX FOR CBSE Maths Class 10 Exercise 1.2 Real Numbers Next Question Answer :-**

**SEE NCERT Maths Class 10 Chapter 1 Ex-1.2 All Questions Solutions **

**NCERT MATHS Class 10 Ex- 1.2 Q No. 1 : Express each number as product of its prime factors : 140,156****NCERT MATHS Class 10 Ex- 1.2 Q No. 2 : Find the LCM and HCF of the following pairs of integers and verify that LCM****NCERT/CBSE MATHS Class 10 Ex- 1.2 Q No. 3 : Find the LCM and HCF of the following integers by applying the prime****NCERT MATHS Class 10 Ex- 1.2 Q No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657).****CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No. 5 : Check whether 6n can end with the digit 0 for any natural number n.****CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.6 Solutions : Explain why 7×11× 13 + 13 and****NCERT/CBSE MATHS Class 10 Ex- 1.2 Q No.7 Solutions :There is a circular path around a sports field. Sonia takes 18 minutes to drive**

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