NCERT MATHS Class 10 Ex- 1.2 Q No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657).
Hy Friends Welcome On NCERT MATHS SOLUTIONS !! Today we are going to solve the Question : ”Given that HCF (306, 657) = 9, find LCM (306, 657).” of Exercise 1.2 Question No 4 Solutions (Real Numbers) of Class 10th, which will prove to be very helpful for you.
CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.4 Solutions
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Real Numbers CHAPTER : 1
Symbol of real numbers (ℝ) In mathematics, the real number is the value presented to any amount corresponding to the simple line. Actual numbers include all rational numbers such as -5 and fractional numbers such as 4/3 and all irrational numbers such as √2 (1.41421356 …, square root of 2, an unregulated algebraic number). By incorporating the ample numbers in the actual numbers, they can be presented from the eternal points that can be attributed on a line in the form of a real number line.
Exercise- 1.2 Question No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657) .
HCF (309, 657) = 9
We know that, LCM × HCF = Product of two numbers
LCM × Hcf = 306 657—
LCM = 22338
CLICK ON RED BOX FOR CBSE Maths Class 10 Exercise 1.2 Real Numbers Next Question Answer :-
SEE NCERT Maths Class 10 Chapter 1 Ex-1.2 All Questions Solutions
- NCERT MATHS Class 10 Ex- 1.2 Q No. 1 : Express each number as product of its prime factors : 140,156
- NCERT MATHS Class 10 Ex- 1.2 Q No. 2 : Find the LCM and HCF of the following pairs of integers and verify that LCM
- NCERT/CBSE MATHS Class 10 Ex- 1.2 Q No. 3 : Find the LCM and HCF of the following integers by applying the prime
- NCERT MATHS Class 10 Ex- 1.2 Q No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657).
- CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No. 5 : Check whether 6n can end with the digit 0 for any natural number n.
- CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.6 Solutions : Explain why 7×11× 13 + 13 and
- NCERT/CBSE MATHS Class 10 Ex- 1.2 Q No.7 Solutions :There is a circular path around a sports field. Sonia takes 18 minutes to drive
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