NCERT MATHS Class 10 Ex- 1.2 Q No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657).


NCERT MATHS Class 10 Ex- 1.2 Q No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657).

Hy Friends Welcome On NCERT MATHS SOLUTIONS !! Today we are going to solve the Question : ”Given that HCF (306, 657) = 9, find LCM (306, 657).” of Exercise 1.2 Question No 4 Solutions (Real Numbers) of Class 10th, which will prove to be very helpful for you.

CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No.4 Solutions

If you are a student of CBSE, today we are going to give you the CBSE / NCERT Chapter : Real Numbers Exercise 1.2 Question No – 4 Solutions . Hope you like this post about Class 10th Maths Solution.

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Real Numbers CHAPTER : 1

Symbol of real numbers (ℝ) In mathematics, the real number is the value presented to any amount corresponding to the simple line. Actual numbers include all rational numbers such as -5 and fractional numbers such as 4/3 and all irrational numbers such as √2 (1.41421356 …, square root of 2, an unregulated algebraic number). By incorporating the ample numbers in the actual numbers, they can be presented from the eternal points that can be attributed on a line in the form of a real number line.

Exercise- 1.2 Question No. 4 : Given that HCF (306, 657) = 9, find LCM (306, 657) .

Class 10 Exercise 1.2 Question No. 4 Solutions

HCF (309, 657) = 9

We know that, LCM × HCF = Product of two numbers

  LCM × Hcf = 306 657—

LCM = 22338

CLICK ON RED BOX FOR CBSE Maths Class 10 Exercise 1.2 Real Numbers Next Question Answer :-

CBSE/NCERT MATHS Class 10 Ex- 1.2 Q No. 5 : Check whether 6n can end with the digit 0 for any natural number n.

SEE NCERT Maths Class 10 Chapter 1 Ex-1.2 All Questions Solutions 

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