**NCERT/CBSE MATHS Class 10 Ex-5.2 Q No.10**** Solutions : ****If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.**

Hy Friends Welcome On **NCERT MATHS SOLUTIONS** !! Today we are going to solve the Question : **”****If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.****” **of** Exercise 5.2 Question No 10 Solutions (Arithmetic Progressions)** of Class 10th, which will prove to be very helpful for you.

**CBSE/NCERT MATHS Class 10 Ex-5.2 Q No. 10 Solutions**

If you are a student of CBSE, today we are going to give you the **CBSE / NCERT** **Chapter : Arithmetic Progressions ** **Exercise 5.2 Question No – 10** **Solutions** . Hope you like this post about Class 10th Maths Solution.

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**Arithmetic Progressions CHAPTER : 5**

n this progression, for a given series, the terms used are the first term, the common difference between the two terms and nth term.

Suppose, a_{1}, a_{2}, a_{3}, ……………., a_{n} is an AP, then;_{ }the **common difference “ d ”** can be obtained as; In this progression, for a given series, the terms used are the first term, the common difference between the two terms and nth term.

**a, a + d, a + 2d, a + 3d, a + 4d, ………. ,a + (n – 1) d**

**Exercise- 5.2 Question No. 10 :**

**If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.**

**Class 10 Exercise 5.2 Question No. 10 Solutions**

We know that,

**For an A.P.**, **a _{n} = a + (n − 1) d**

*a*

_{17}=

*a*+ (17 − 1)

*d*

*a*

_{17}=

*a*+ 16

*d*

Similarly,

*a*

_{10}=

*a*+ 9

*d*

**It is given that**

*a*

_{17}−

*a*

_{10}= 7

(

*a*+ 16

*d*) − (

*a*+ 9

*d*) = 7

7

*d*= 7

*d*= 1

Therefore,

**the common difference is 1.**

## **OR**

**Solution:**

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