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# NCERT/CBSE MATHS Class 10 Ex-5.2 Q No.17 Solutions : Find the 20th term from the last term of the A.P. 3, 8, 13, …, 253.

Hy Friends Welcome On NCERT MATHS SOLUTIONS !! Today we are going to solve the Question : Find the 20th term from the last term of the A.P. 3, 8, 13, …, 253.of Exercise 5.2 Question No 17 Solutions (Arithmetic Progressions) of Class 10th, which will prove to be very helpful for you.

# CBSE/NCERT MATHS Class 10 Ex-5.2 Q No. 17 Solutions

If you are a student of CBSE, today we are going to give you the CBSE / NCERT Chapter : Arithmetic Progressions Exercise 5.2 Question No – 17 Solutions . Hope you like this post about Class 10th Maths Solution.

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### Arithmetic Progressions CHAPTER : 5

n this progression, for a given series, the terms used are the first term, the common difference between the two terms and nth term.

Suppose, a1, a2, a3, ……………., an is an AP, then; the common difference “ d ” can be obtained as; In this progression, for a given series, the terms used are the first term, the common difference between the two terms and nth term.

a, a + d, a + 2d, a + 3d, a + 4d, ………. ,a + (n – 1) d

### Class 10 Exercise 5.2 Question No. 17 Solutions

Given A.P. is
3, 8, 13, …, 253
Common difference for this A.P. is 5.
Therefore, this A.P. can be written in reverse order as
253, 248, 243, …, 13, 8, 5
For this A.P.,
a = 253
d = 248 − 253 = −5
= 20
a20 = a + (20 − 1) d
a20 = 253 + (19) (−5)
a20 = 253 − 95
a = 158
Therefore, 20th term from the last term is 158.

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