Hy Friends Welcome On NCERT MATHS SOLUTIONS !! Today we are going to solve the Question : Use Euclid’s division algorithm to find the HCF of : 135 and 225 , 196 and 38220, 867 and 255 of Exercise 1.1 Question No 1 of Class 10th, which will prove to be very helpful for you.
If you are a student of CBSE, today we are going to give you the CBSE / NCERT Chapter : Real Numbers Exercise1.1 Question No1 Solutions . Hope you like this post about Class 10th Maths Solution.
Here we would like to tell you that there are other websites on which the students demanded the Solution of NCERT MATHS Chapters, we had promised them that we will soon send you the questions of Class 9, And we completed our promise to them.We asked the good knowledgeable teachers of mathematics and asked them to solve the issues of CBSE’s mathematical questions and also said that the answers to our questions are such that the students have no difficulty in solving all those questions.
Real Numbers CHAPTER : 1
Symbol of real numbers (ℝ) In mathematics, the real number is the value presented to any amount corresponding to the simple line. Actual numbers include all rational numbers such as 5 and fractional numbers such as 4/3 and all irrational numbers such as √2 (1.41421356 …, square root of 2, an unregulated algebraic number). By incorporating the ample numbers in the actual numbers, they can be presented from the eternal points that can be attributed on a line in the form of a real number line.
Class 10 Exercise 1.1 Question No. 1 : Use Euclid’s division algorithm to find the HCF of:

135 and 225

196 and 38220

867 and 255
Class 10 Exercise 1.1 Question No. 1 Solutions
(i) Use Euclid’s division algorithm to find the HCF of : 135 and 225
Since 225 > 135, we apply the division lemma to 225 and 135 to obtain
225 = 135 × 1 + 90
Since remainder 90 ≠ 0,
we apply the division lemma to 135 and 90 to obtain
135 = 90 × 1 +45
We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain
90 = 2 × 45 + 0
Since the remainder is Zero, the process stop.
Since the divisor at this stage is 45,
Therefore, the HCF of 135 and 225 is 45.
(ii) Use Euclid’s division algorithm to find the HCF of : 196 and 38220
Since 38220 > 196, we apply the divisio lemma to 38220 and 196 to obtain
38220 = 196 × 195 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 196,
Therefor, HCF of 196 and 38220 is 196.
(iii) Use Euclid’s division algorithm to find the HCF of : 867 and 255
Since 867 > 255, we apply the division lemma to 867 and 255 to obtain
867 =255 × 3 +102
Since remainder 102 ≠ 0, we apply the divison lemma to 255 and 102 to obtain
255 = 102 × 2 + 51
We consider the new divisor 102 and new remainder 51, and apply the division lemma to obtain
102 = 51 ×2+ 0
Since the remainder is zero, the process stop.
Since the divisor at this stage is 51, therefore,
HCF of 867 and 255 is 51.
CLICK ON RED BOX FOR CBSE Maths Class 10 Exercise 1 Real Numbers Next Question Answer :
SEE NCERT Maths Class 10 Chapter 1 Ex1.1 All Questions Solutions
 NCERT MATHS Class 10 Ex 1.1 Q No. 1 : Use Euclid’s division algorithm to find the HCF of 135 and 225 , 196 and 38220,867 and 255
 NCERT MATHS Class 10 Ex 1.1 Q No. 2 : Show that any positive add integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.
 NCERT MATHS Class 10 Ex 1.1 Q No. 3 : An army contingent of 616 members is to march behind an army
 NCERT MATHS Class 10 Ex 1.1 Q No. 4 : Use Euclid’s division lemma to show that the square of any
 NCERT MATHS Class 10 Ex 1.1 Q No. 5 : Use Euclid’s division lemma to show that the cube of any pooitive
About NCERT Maths Solutions :
यहाँ पर हम आपको बताना चाहेंगे कि हमारी अन्य websites भी हैं जिन पर छात्रों ने NCERT MATHS Chapters के Solution की काफी मांग की थी , हमने उनसे वादा किया था कि हम जल्द ही आपको Class 9th ,10th के गणित के सवालों के हल करके आप तक पहुचाएंगे और हमने उनसे किया अपना वादा पूरा किया 
हमने गणित के अच्छे जानकार ढूंढे और उनसे CBSE के गणित के सवालों के आसन हल करने को कहा साथ ही यह बात भी कही की हमारे सवालों के जवाब कुछ ऐसे हो जिनमे छात्रों को उन सभी सवालों को हल करने में कोई कठिनाई न हो 
If you have any question from NCERT, then you can ask your question here in the comment box. We will be happy to answer your questions.